document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=78011>Question 78011</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0028253264/algebrahomeworkh>GLENCOE </A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> y=3y(squared) over 3y+1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #55963 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=55963\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> As I understand the equation you are to solve, it is:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+3y%5E2%2F%283y%2B1%29 ALIGN=MIDDLE  ALT=\"y+=+3y%5E2%2F%283y%2B1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "One thing to note in passing is that y cannot be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%2F3 ALIGN=MIDDLE  ALT=\"-1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > because that would give you<BR>\n" );
document.write( "a denominator of zero and division by 0 is not allowed.<BR>\n" );
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document.write( "Let's get rid of the denominator by multiplying both sides by (3y + 1).  When you do that<BR>\n" );
document.write( "the denominator on the right side cancels with this multiplier and the equation becomes:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%2A%283y+%2B+1%29+=+3y%5E2 ALIGN=MIDDLE  ALT=\"y%2A%283y+%2B+1%29+=+3y%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Multiply out the left side and the equation becomes:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3y%5E2+%2B+y+=+3y%5E2 ALIGN=MIDDLE  ALT=\"3y%5E2+%2B+y+=+3y%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Subtract 3y^2 from both sides and you are left with:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+0 ALIGN=MIDDLE  ALT=\"y+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "That's the solution to the problem.  You can check by going back to the original problem<BR>\n" );
document.write( "and substituting 0 for y and you will find that the equation reduces to 0 = 0/1 which is 0 = 0.<BR>\n" );
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document.write( "Hope this helps. </SPAN>\n" );
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