document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=483275>Question 483275</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A company manufactures three types of t.vs A,B and C. The company manufactures four less type B than twice A, and one more type B than the sum of types A and type C. If the total number of t.vs manufactured per week is 51. How many of each type of t.v are manufactured.<BR>\n" );
document.write( "Can someone please help this question has me in a twist! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #559627 by </B><A HREF=/tutors/aboutme.mpl?userid=kayroge><B>kayroge(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kayroge><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=kayroge><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=559627\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> So let A be A, B be B and C be C<BR>\n" );
document.write( "2A-4=B<BR>\n" );
document.write( "and<BR>\n" );
document.write( "2A-4+1=A+C<BR>\n" );
document.write( "2A-A-4+1=C<BR>\n" );
document.write( "so A-5=C<BR>\n" );
document.write( "so <BR>\n" );
document.write( "A+2A-4+A-5=51<BR>\n" );
document.write( "4A-4-5=51<BR>\n" );
document.write( "4A=51+4+5<BR>\n" );
document.write( "A=60/4<BR>\n" );
document.write( "A=15<BR>\n" );
document.write( "So B=B+15x2-4=26<BR>\n" );
document.write( "So C=51-26-15=10<BR>\n" );
document.write( "Answer equals A=15 B=26 and C=10 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );