document.write( "Question 922576: So, there's a rectangle named FGHJ. FG(top base) is 4x+11 and GH(right side) is 3x-1. The perimeter is 48. Find x, then find the area of the rectangle. \r
\n" ); document.write( "\n" ); document.write( "I've tried setting them equal to each other, but that didn't work because they both aren't going to be the same thing.
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Algebra.Com's Answer #559621 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
L = length
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\n" ); document.write( "\n" ); document.write( "Let's say the horizontal sides are the length, so \"L+=+4x%2B11\". Recall that the parallel sides of a rectangle are congruent.\r
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\n" ); document.write( "\n" ); document.write( "The vertical sides are the width, so \"W+=+3x+-+1\"\r
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\n" ); document.write( "\n" ); document.write( "The perimeter of the rectangle is found by this formula \"P+=+2%2A%28L%2BW%29\" where P is the perimeter, L is the length, W is the width.\r
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\n" ); document.write( "\n" ); document.write( "\"P+=+2%2A%28L%2BW%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"48+=+2%2A%284x%2B11%2B3x+-+1%29\" Plug in \"P+=+48\", \"L+=+4x%2B11\", and \"W+=+3x+-+1\". Solve for x.\r
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\n" ); document.write( "\n" ); document.write( "\"48+=+2%2A%287x%2B10%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"48+=+14x%2B20\"\r
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\n" ); document.write( "\n" ); document.write( "\"48-20+=+14x\"\r
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\n" ); document.write( "\n" ); document.write( "\"28+=+14x\"\r
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\n" ); document.write( "\n" ); document.write( "\"14x+=+28\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+28%2F14\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+2\"\r
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\n" ); document.write( "\n" ); document.write( "------------------------------------------------------------------------\r
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\n" ); document.write( "\n" ); document.write( "Let me know if that helps or not. Thanks.\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, feel free to email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "My Website: http://www.freewebs.com/jimthompson5910/home.html\r
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