document.write( "Question 922475: Please explain how I would go about figuring out the graph to:\r
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document.write( "-6cos(4x-π/2)
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document.write( "amp = 6
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document.write( "period = 1/2
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document.write( "phase shift = π/8\r
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document.write( "If I have the above correct from that point what would I do? I am confused because I don't know what to do with the period? I've worked with radians but what does 1/2 period mean? please explain
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document.write( "how this is solved.\r
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document.write( "Thank you \n" );
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Algebra.Com's Answer #559591 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Please explain how I would go about figuring out the graph to: \n" ); document.write( "-6cos(4x-π/2) \n" ); document.write( "*** \n" ); document.write( "Form of equation for cos function: \n" ); document.write( "y=Acos(Bx-C), A=amplitude, period=2π/B, phase shift=C/B \n" ); document.write( ".. \n" ); document.write( "For given function:y=-6cos(4x-π/2) \n" ); document.write( "A=6 \n" ); document.write( "B=4 \n" ); document.write( "Period=2π/4=π/2 \n" ); document.write( "1/4 period=π/8 \n" ); document.write( "C=π/2 \n" ); document.write( "Phase shift=C/B=(π/2)/4=π/8 (shift to the right) \n" ); document.write( "The negative sign means the basic curve is reflected about the x-axis. \n" ); document.write( ".. \n" ); document.write( "Graphing the function for one period: \n" ); document.write( "Start with basic cos curve with amplitude 1 and no phase shift. \n" ); document.write( "Mark x-axis at 1/4 period intervals(π/8)in radians. \n" ); document.write( "(0,1),(π/8,0),(2π/8,-1),(3π/8,0),(4π/8,1) \n" ); document.write( ".. \n" ); document.write( "multiply y-coordinates by -6(amplitude) \n" ); document.write( "(0,-6),(π/8,0),(2π/8,6),(3π/8,0),(4π/8,-6) \n" ); document.write( ".. \n" ); document.write( "shift x-coordinates π/8 to the right. \n" ); document.write( "(π/8,-6),(2π/8,0),(3π/8,6),(4π/8,0),(5π/8,-6)(Final configuration) \n" ); document.write( ".. \n" ); document.write( "y-intercept \n" ); document.write( "set x=0 \n" ); document.write( "y=-6cos(4x-π/2) \n" ); document.write( "y=-6cos(-π/2)=-6*0=0\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |