document.write( "Question 922474: simplify. Write your answers in the form of a+bi where a and b are red numbers.
\n" ); document.write( "(1-i)/(-9+2i)\r
\n" ); document.write( "\n" ); document.write( "the answer is -11/85+7/85i \n" ); document.write( "
Algebra.Com's Answer #559564 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"%281-i%29%2F%28-9%2B2i%29\"\r\n" );
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document.write( "The conjugate of the denominator -9+2i is formed by changing \r\n" );
document.write( "the sign of only the imaginary part, getting -9-2i.\r\n" );
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document.write( "So we multiply by \"%28-9-2i%29%2F%28-9-2i%29\" which just equals 1.\r\n" );
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document.write( "\"%281-i%29%2F%28-9%2B2i%29\"\"%22%D7%22\"\"%28-9-2i%29%2F%28-9-2i%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"%28%281-i%29%28-9-2i%29%29%2F%28%28-9%2B2i%29%28-9-2i%29%29\" \r\n" );
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document.write( "Use FOIL on numerator and denominator:\r\n" );
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document.write( "\"%28-9-2i%2B9i%2B2i%5E2%29%2F%2881%2B18i-18i-4i%5E2%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"%28-9%2B7i%2B2i%5E2%29%2F%2881-4i%5E2%29\"\r\n" );
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document.write( "Replace iČ by -1\r\n" );
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document.write( "\"%28-9%2B7i%2B2%28-1%29%29%2F%2881-4%28-1%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"%28-9%2B7i-2%29%2F%2881%2B4%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"%28-11%2B7i%29%2F85\"\r\n" );
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document.write( "\"-11%2F85%2B%287i%29%2F85\"\r\n" );
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document.write( "\"-11%2F85%2Bexpr%287%2F85%29i\"\r\n" );
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document.write( "Edwin
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