document.write( "Question 922330: Please can you help me with this problem: The sum of the ages of dorothy and dorilyn is 41. In 5 years, dorothy will be twice as old as dorilyn. Find thier ages 3 years ago.
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\n" ); document.write( "say: x= age of dorothy at present
\n" ); document.write( " y= age of dorilyn at present
\n" ); document.write( " but sum of their ages is 41
\n" ); document.write( " therefore:
\n" ); document.write( " x+y=41>>>> this is your equation 1
\n" ); document.write( " in 5 years, meaning after 5 years, dorothy will be wice a old as dorilyn
\n" ); document.write( " from their present ages after 5 years,
\n" ); document.write( " dorothy will be (x+5) years old and dorilyn will be (y+5) years old as well
\n" ); document.write( " and dorothy will be twice as old as dorilyn
\n" ); document.write( " (x+5), the age of dorothy will be equal to twice the age of dorilyn which
\n" ); document.write( " is 2(y+5)
\n" ); document.write( " (x+5)=2(y+5) simplifying this equation gives: x-2y-5=0>>>> your equation 2
\n" ); document.write( " now you have two equations
\n" ); document.write( " x+y=41 and x-2y-5=0, two simple equations with two unknown
\n" ); document.write( " further solving, we get x=29 years old(dorothy) & y=12 years old(dorilyn)
\n" ); document.write( " so to get there ages three years back, subtract 3 from their present ages
\n" ); document.write( " dorothy's ages was: (29-3)=26 and dorilyn's age was(12-3)=9
\n" ); document.write( " checking: substitute values of x and y in equations 1 & 2
\n" ); document.write( " x+y=41, 29+12=41, and x-2y-5=0, 29-2(12)-5=0
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\n" ); document.write( " hope you'll like my solution \n" ); document.write( "
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