document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=922396>Question 922396</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help on steps for finding direct variation ,find the constatant of variation, then the value of y when x=3\r<BR>\n" );
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document.write( "Y=3\4 when x=1\8\r<BR>\n" );
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document.write( "Thank you\r<BR>\n" );
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document.write( "I tried\r<BR>\n" );
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document.write( "3\4 by 1\8. Y\3. K=6  y=18 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #559530 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=559530\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y = kx<BR>\n" );
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document.write( " 6 = k<BR>\n" );
document.write( "y = 6x<BR>\n" );
document.write( "x = 3<BR>\n" );
document.write( "y = 6•3 = 18 </SPAN>\n" );
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