document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=922336>Question 922336</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem: the sum of the ages of dorothy and dorilyn is 41. In 5 years, dorothy will be twice as old as dorilyn. Find thier ages 3 years ago. Thank you for helping!! :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #559510 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=559510\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the age of dorothy and y is the age of dorilyn, then<BR>\n" );
document.write( "x + y = 41<BR>\n" );
document.write( "x +5 = 2(y +5)<BR>\n" );
document.write( "solve first equation for y<BR>\n" );
document.write( "y = 41 - x<BR>\n" );
document.write( "substitute for y in second equation<BR>\n" );
document.write( "x + 5 = 2(41 - x +5)<BR>\n" );
document.write( "x +5 = 2(46 - x)<BR>\n" );
document.write( "x +5 = 92 -2x<BR>\n" );
document.write( "3x = 87<BR>\n" );
document.write( "x = 29 and y = 12<BR>\n" );
document.write( "therefore their ages 3 years ago are<BR>\n" );
document.write( "dorothy is 26 and dorilyn is 9<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );