document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=922318>Question 922318</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the probability of drawing a diamond card in each of the consecutive draws from a well shuffled pack of cards, if the card drawn is not replaced after the first draw. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #559493 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=559493\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(drawing a diamond card in each of the consecutive draws ) <BR>\n" );
document.write( "card drawn is not replaced <BR>\n" );
document.write( "P = (13/52)(12/51)(11/50)(10/49)...(4/43)(3/42)(2/41)(1/40)<BR>\n" );
document.write( "........<BR>\n" );
document.write( "Re TY: IF you are wishing to find the Probability of drawing ALL 13 Diamonds<BR>\n" );
document.write( "consecutively: Yes, P would be basically  = Zero of doing that.<BR>\n" );
document.write( " P(drawing 13 Diamonds consecutively) = 13!/( 52!/39!) = 1.57476952244911E-12<BR>\n" );
document.write( ".........<BR>\n" );
document.write( "generally: Questions concern a 5-card Flush, for ex.<BR>\n" );
document.write( "P = (13/52)(12/51)(11/50)(10/49)(9/48) = 4.952x10^(-4)  rounded<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );