document.write( "Question 922361: The sum of the ages of dorothy and dorilyn is 41. In 5 years dorothy will be twice as old as dorilyn. Find their ages 3 years ago \n" ); document.write( "

Algebra.Com's Answer #559488 by srinivas.g(540) $\"\"$ $\"About$

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Let x and y be the present ages of dorothy and dorilyn.
\n" ); document.write( " so x+y= 41
\n" ); document.write( " In 5 years dorothy will be twice as old as dorilyn
\n" ); document.write( " so, x+5 = 2*(y+5)
\n" ); document.write( " x+5 =2*y+2*5
\n" ); document.write( " x+5 = 2y+10
\n" ); document.write( " move 5 to the right
\n" ); document.write( " x=2y+10-5
\n" ); document.write( " x=2y+5
\n" ); document.write( " keep this x=2y+5 in x+y= 41
\n" ); document.write( " (2y+5)+y= 41
\n" ); document.write( " 3y+5 =41
\n" ); document.write( " subtract 5 on both sides
\n" ); document.write( " 3y+5 -5 =41-5
\n" ); document.write( " 3y = 36
\n" ); document.write( " divide with 3 on both sides
\n" ); document.write( " 3y/3 = 36/3
\n" ); document.write( " y= 12
\n" ); document.write( " x= 2y+5
\n" ); document.write( " =2*12+5
\n" ); document.write( " =29
\n" ); document.write( "so dorothy & dorilyn's present ages are 29 years & 12 years
\n" ); document.write( " after 3 years dorothy age will be 29+3 = 32 years
\n" ); document.write( " after 3 years dorilyn's age will be 12+3 =15 years
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