document.write( "Question 922306: Find the zeros of the polynomial f(x)=x^3 + x^2 - 12x = 0 \n" ); document.write( "
Algebra.Com's Answer #559476 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E3+%2B+x%5E2+-+12x+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%5E2+%2B+x+-+12%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x+-+3%29%28x+%2B+4%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=0\" or \"x+-+3+=+0\" or \"x+%2B+4+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=0\" or \"x+=+3\" or \"x+=+-4\"\r
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\n" ); document.write( "\n" ); document.write( "The three roots are: \"x=0\" or \"x+=+3\" or \"x+=+-4\"\r
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\n" ); document.write( "\n" ); document.write( "Let me know if that helps or not. Thanks.\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, feel free to email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "My Website: http://www.freewebs.com/jimthompson5910/home.html
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