document.write( "Question 922288: A sequence of numbers is said to form a harmonic progression provided their reciprocals form an arithmetic progression. Insert three harmonic means between - 1/2 and 1/14. \n" ); document.write( "
Algebra.Com's Answer #559471 by KMST(5328)\"\" \"About 
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I understand the first term to be the positive number \"1%2F2\" .
\n" ); document.write( "We need an arithmetic progression, where each term differs from the one before by a common difference \"d\" .
\n" ); document.write( "The first term is \"2\" , which is followed by 3 more terms, and then by \"14\" .
\n" ); document.write( "The terms are \"2\" , \"2%2Bd\" , \"2%2B2d\" , \"2%2B3d\" , \"14\"
\n" ); document.write( "The fifth term is \"2%2B%285-1%29d=2%2B4d=14\" .
\n" ); document.write( "\"2%2B4d=14\"--->\"4d=14-2\"--->\"4d=12\"--->\"d=12%2F4\"--->\"d=3\" .
\n" ); document.write( "So the terms of the arithmetic progression are
\n" ); document.write( "\"2\" , \"2%2B3=5\" , \"5%2B3=8\" , \"8%2B3=11\" , \"11%2B3=14\" ,
\n" ); document.write( "and the terms of the harmonic progression are
\n" ); document.write( "\"1%2F2\" , \"1%2F5\" , \"1%2F8\" , \"1%2F11\" , and \"1%2F14\" .
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\n" ); document.write( "NOTE: If the first term was \"-1%2F2\" ,
\n" ); document.write( "then the arithmetic progression would be
\n" ); document.write( "\"-2\" , \"2\" , \"6\" , \"10\" , \"14\" ,
\n" ); document.write( "and the harmonic progression would be
\n" ); document.write( "\"-1%2F2\" , \"1%2F2\" , \"1%2F6\" , \"1%2F10\" , \"1%2F14\" .
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