document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=78044>Question 78044</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 3 less than another. If 10 times the smaller number minus 4 times the larger numberis 24, find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #55947 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=55947\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One number is 3 less than another. If 10 times the smaller number minus 4 times the larger numberis 24, find the two numbers.<BR>\n" );
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document.write( "Let one of the numbers be \"x\" ; Then the smaller number is \"x-3\".<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "10(x-3)-4x=24<BR>\n" );
document.write( "10x-30-4x=24<BR>\n" );
document.write( "6.=54<BR>\n" );
document.write( "x=9 (the larger number)<BR>\n" );
document.write( "x-3=6 (the smaller number)<BR>\n" );
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document.write( "cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );