document.write( "Question 922292: How much money, invested at an interest rate of r % per year compounded continuously, will amount to A dollars after t years? (Round your answer to the nearest cent.)
\n" ); document.write( "A = 13,000, r = 4.3, t = 4
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Algebra.Com's Answer #559467 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"A+=+P%2Ae%5E%28r%2At%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"13000+=+P%2Ae%5E%280.043%2A4%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"13000+=+P%2Ae%5E%280.172%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"13000+=+P%2A1.18767783321398\"\r
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\n" ); document.write( "\n" ); document.write( "\"13000%2F1.18767783321398+=+P\"\r
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\n" ); document.write( "\n" ); document.write( "\"P+=+13000%2F1.18767783321398\"\r
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\n" ); document.write( "\n" ); document.write( "\"P+=+10945.7292511899\"\r
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\n" ); document.write( "\n" ); document.write( "\"P+=+10945.73\"\r
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\n" ); document.write( "\n" ); document.write( "You need to invest $10,945.73 into the account.\r
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\n" ); document.write( "\n" ); document.write( "Let me know if that helps or not. Thanks.\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, feel free to email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "My Website: http://www.freewebs.com/jimthompson5910/home.html
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