document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=922270>Question 922270</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve this problem. find the perimeter and area of a rectangle with a length of 6ft and a diagonal of 10 ft. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #559459 by </B><A HREF=/tutors/aboutme.mpl?userid=IBMath><B>IBMath(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=IBMath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=559459\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the length of a rectangle is 6 feet, we just need to find the width.<BR>\n" );
document.write( "Since, A = lw, Perimeter = 2(l+w)\r<BR>\n" );
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document.write( "The diagonal of a rectangle splits it in half, making it into 2 right triangles. And if the hypotenuse(diagonal) is 10 ft. Just plug in the pythagorean theorem where a^2 + b^2 = c^2<BR>\n" );
document.write( "So: 6^2 + b^2 = 10^2<BR>\n" );
document.write( "Where is b =  the width of the Rectangle and Triangle\r<BR>\n" );
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document.write( "36 + b^2 = 100<BR>\n" );
document.write( "b^2 = 64<BR>\n" );
document.write( "b = 8\r<BR>\n" );
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document.write( "So the area would be 8 * 6 = 48 feet<BR>\n" );
document.write( "And the perimeter would be 2(8+6) = 28 feet\r<BR>\n" );
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document.write( "Good Luck! </SPAN>\n" );
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