document.write( "Question 78019: Graph the relation and state its domain and range.\r
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Algebra.Com's Answer #55942 by stanbon(75887)\"\" \"About 
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Graph the relation and state its domain and range.
\n" ); document.write( "x=y^2-1
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\n" ); document.write( "Since y is not in a denominator and y is not in a radical, y can take
\n" ); document.write( "any value.
\n" ); document.write( "So, Range is All Real Numbers.
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\n" ); document.write( "Since y^2 is always >0 zero
\n" ); document.write( "y^2-1 must be >=1.
\n" ); document.write( "So, Domain is All Real Numbers that are >=1
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\n" ); document.write( "To graph, solve for y:
\n" ); document.write( "y=sqrt(x+1) OR y=-sqrt(x+1)
\n" ); document.write( "\"graph%28400%2C300%2C-5%2C20%2C-20%2C20%2Csqrt%28x%2B1%29%2C-sqrt%28x%2B1%29%29\"
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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