document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=922005>Question 922005</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1)in a polygon there are  6 right angles and the remaining angles are all equal to 200 degree each the number of sides the polygon has ? \r<BR>\n" );
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document.write( "2) the ratio between the radius of the base and the height of the cylinder is 2 :3 if the volume is 1617 cm cube the total surface area  of cylinder is ?  </SPAN>\n" );
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document.write( "     let r=radius of the base of the cylinder<BR>\n" );
document.write( "         h= height of the cylinder<BR>\n" );
document.write( "     the ratio between the radius of the base and the height is 2:3<BR>\n" );
document.write( "     this means that if you divide the radius by the height of the cylinder    <BR>\n" );
document.write( "     quotient is 2/3 so: r/h=2/3<BR>\n" );
document.write( "     solving for h:<BR>\n" );
document.write( "     h=3r/2  (equation 1)<BR>\n" );
document.write( "     the volume of the cylinder is 1617 cm cube<BR>\n" );
document.write( "     v=area of the base multiplied by its height<BR>\n" );
document.write( "     v=pi*r^2(h)  (equation 2)<BR>\n" );
document.write( "       substitute value of h from (equation 1) in (equation 2)<BR>\n" );
document.write( "     v=pi*r^2(3r/2)<BR>\n" );
document.write( "     v= 3/2(pi)r^3<BR>\n" );
document.write( "     equating v to the given volume which is 1617 cm cube:<BR>\n" );
document.write( "     3/2(pi)r^3=1617<BR>\n" );
document.write( "     r^3=1617*2/(3*pi),  r^3 = 343, r= 7cm<BR>\n" );
document.write( "     solving for h in equation 1:<BR>\n" );
document.write( "     h=3r/2<BR>\n" );
document.write( "     h= 3*7/2= 10.5 cm<BR>\n" );
document.write( "     surface area= base perimeter times height<BR>\n" );
document.write( "     SA= 2*pi*r*h where pi=3.1416<BR>\n" );
document.write( "     SA= 2*3.1416*7*10.5<BR>\n" );
document.write( "     SA= 461.82 sq. cm </SPAN>\n" );
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