document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=78040>Question 78040</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do u break this problem down into (p+ )(p+ )?<BR>\n" );
document.write( " p2+19p+18 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #55933 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=55933\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Factor the last number:<BR>\n" );
document.write( "18 = (2 x 9) or (3 x 6) or (18 x 1) [which factors add-up to 19?]<BR>\n" );
document.write( "2+9=11 [doesn't work]<BR>\n" );
document.write( "3+6=9 [doesn't work either]<BR>\n" );
document.write( "18+1=19 [works]<BR>\n" );
document.write( ". <BR>\n" );
document.write( "So, 18 and 1 multiplied toegther equals (18) and when added together equals the middle term of (19.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "(p+18)(p+1) [use the FOIL method to muliply the factors and you will get your original answer]<BR>\n" );
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