document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=922010>Question 922010</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Question:\r<BR>\n" );
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document.write( "\"The nth term of a series is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%281%2F2%29%282n-1%29+ ALIGN=MIDDLE  ALT=\"+%281%2F2%29%282n-1%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Write down the (n+1)th term.\r<BR>\n" );
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document.write( "a) prove that the series is an arithmetic progression.\r<BR>\n" );
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document.write( "b) find, algebraically, the value for n for which the sum to n terms is 200\"\r<BR>\n" );
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document.write( "-I have written the (n+1)th term <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%281%2F2%29%282n%2B1%29+ ALIGN=MIDDLE  ALT=\"+%281%2F2%29%282n%2B1%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "-I have also done part a) of the question by subtracting the nth term from the (n+1)th term to find that the common difference between the terms is 1.<BR>\n" );
document.write( "-I also know that the formula for an arithmetic progression is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+Un=a%2B%28n-1%29d+ ALIGN=MIDDLE  ALT=\"+Un=a%2B%28n-1%29d+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "please help with part b) of the question </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #559326 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=559326\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"The nth term of a series is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%281%2F2%29%282n-1%29+ ALIGN=MIDDLE  ALT=\"+%281%2F2%29%282n-1%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Write down the (n+1)th term.\r<BR>\n" );
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document.write( "a) prove that the series is an arithmetic progression.\r<BR>\n" );
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document.write( "b) find, algebraically, the value for n for which the sum to n terms is 200\"<BR>\n" );
document.write( "S(n) = n(a(1)+a(n))/2<BR>\n" );
document.write( "200 = n((1/2)+(1/2)(2n-1))/2<BR>\n" );
document.write( "400 = n((1/2)(1+2n-1)<BR>\n" );
document.write( "400 = n*n<BR>\n" );
document.write( "n = 20<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( "-I have written the (n+1)th term <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%281%2F2%29%282n%2B1%29+ ALIGN=MIDDLE  ALT=\"+%281%2F2%29%282n%2B1%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "-I have also done part a) of the question by subtracting the nth term from the (n+1)th term to find that the common difference between the terms is 1.<BR>\n" );
document.write( "-I also know that the formula for an arithmetic progression is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+Un=a%2B%28n-1%29d+ ALIGN=MIDDLE  ALT=\"+Un=a%2B%28n-1%29d+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "please help with part b) of the question </SPAN>\n" );
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