document.write( "Question 921967: A woman is six times as old as her son. In 9 years she will be three times as old as her son. How old are they now? \n" ); document.write( "

Algebra.Com's Answer #559294 by srinivas.g(540) $\"\"$ $\"About$

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let woman age be x now. Her son's age be y now
\n" ); document.write( " woman is six times as old as her son.
\n" ); document.write( " x =6*y
\n" ); document.write( " x =6y
\n" ); document.write( "In 9 years she will be three times as old as her son
\n" ); document.write( " so, after 9 years her age will be x+9 & her son's age will be y+9
\n" ); document.write( "so, x+9 = 3*(y+9)
\n" ); document.write( " put x=6y in the above equation
\n" ); document.write( " 6y+9= =3*(y+9)
\n" ); document.write( " 6y+9= 3y+ 3*9
\n" ); document.write( " 6y+9 = 3y+27
\n" ); document.write( " subtract 3y on both sides
\n" ); document.write( " 6y+9 -3y= 3y+27-3y
\n" ); document.write( " 3y+9= 27
\n" ); document.write( " subtract 9 on both sides
\n" ); document.write( " 3y+9-9=27-9
\n" ); document.write( " 3y= 18
\n" ); document.write( " divide with 3 on both sides
\n" ); document.write( " 3y/3 = 18/3
\n" ); document.write( " y= 6
\n" ); document.write( " so age of son now (y) = 6
\n" ); document.write( " age of woman (x=6y) = 6*6 =36
\n" ); document.write( "age of son is 6 years and woman is 36 years
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