document.write( "Question 78028: Find two consecutive integers such that the sum of 3 times the first integer and 7 times second integer is 47. \n" ); document.write( "

Algebra.Com's Answer #55919 by ptaylor(2198) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let x=first integer
\n" ); document.write( "Three times the first integer=3x\r
\n" ); document.write( "\n" ); document.write( "Then x+1=the second integer
\n" ); document.write( "Seven times the second integer=7(x+1)\r
\n" ); document.write( "\n" ); document.write( "Now we are told that if we add three times the first and seven times the second we end up with 47, so:\r
\n" ); document.write( "\n" ); document.write( "3x+7(x+1)=47 get rid of parens\r
\n" ); document.write( "\n" ); document.write( "3x+7x+7=47 subtract 7 from both sides\r
\n" ); document.write( "\n" ); document.write( "3x+7x+7-7=47-7 collect like terms\r
\n" ); document.write( "\n" ); document.write( "10x=40 divide both sides by 10\r
\n" ); document.write( "\n" ); document.write( "x=4-------------------------------------first integer\r
\n" ); document.write( "\n" ); document.write( "4+1=5--------------------------------------second integer\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "3*4+7*5=47
\n" ); document.write( "12+35=47
\n" ); document.write( "47=47\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor \n" ); document.write( "

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