document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=921691>Question 921691</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A woman can do a certain job in 10 hr and the younger daughter can do it in 12 hr. After the woman and her younger daughter have been working for 1 hr, the younger daughter got tired and decided to leave the woman doing the job alone. How long (in hours) did the woman finish the job after the younger daughter left her? \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #559159 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=559159\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It is obvious that the daughter can't do the job alone in 12 hours if she is worn out after one hour!\r<BR>\n" );
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document.write( "1/10+1/12+x/10=1<BR>\n" );
document.write( "1/12+(x+1)/10=1<BR>\n" );
document.write( "1/6+(x+1)/5=2\r<BR>\n" );
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document.write( "x=49/6<BR>\n" );
document.write( "x=8 1/6 <BR>\n" );
document.write( "x=8.1667\r<BR>\n" );
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