document.write( "Question 78020: Can someone help me with this problem i have no idea where to even start.\r
\n" ); document.write( "\n" ); document.write( "The height \"h\" in feet of an object after \"t\" seconds is given by the function\r
\n" ); document.write( "\n" ); document.write( "h = -16t^2+70t+8\r
\n" ); document.write( "\n" ); document.write( "How long will it take the object to hit the ground? Round the answer to the nearest thousandth.
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Algebra.Com's Answer #55915 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
To figure out when the object will hit the ground, let h=0 and solve for t. This means we can use the quadratic formula:\r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"-16x%5E2%2B70x%2B8+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2870%29%5E2-4%2A-16%2A8=5412\".
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\n" ); document.write( " Discriminant d=5412 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-70%2B-sqrt%28+5412+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%2870%29%2Bsqrt%28+5412+%29%29%2F2%5C-16+=+-0.11144676971869\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%2870%29-sqrt%28+5412+%29%29%2F2%5C-16+=+4.48644676971869\"
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\n" ); document.write( " Quadratic expression \"-16x%5E2%2B70x%2B8\" can be factored:
\n" ); document.write( " \"-16x%5E2%2B70x%2B8+=+-16%28x--0.11144676971869%29%2A%28x-4.48644676971869%29\"
\n" ); document.write( " Again, the answer is: -0.11144676971869, 4.48644676971869.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+-16%2Ax%5E2%2B70%2Ax%2B8+%29\"

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\n" ); document.write( "\n" ); document.write( "Ignoring the negative time, we get\r
\n" ); document.write( "\n" ); document.write( "\"t=4.49\"\r
\n" ); document.write( "\n" ); document.write( "So the object will hit the ground at about 4.49 seconds
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