document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=921677>Question 921677</A>: <I><SPAN STYLE=\"word-break: break-all;\"> PLEASE HELP ME SOLVE THIS AGE WORD PROBLEM \"A year ago, John was three times as old as Larry. A year later, he was twice as old as Larry. How old are John and Larry?' </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #559147 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=559147\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let Larry's age be x and John's age be y, then we have<BR>\n" );
document.write( "y = 3x<BR>\n" );
document.write( "y+1 = 2(x+1)<BR>\n" );
document.write( "substitute the first equation for y in second equation<BR>\n" );
document.write( "3x + 1 = 2x + 2<BR>\n" );
document.write( "x = 1<BR>\n" );
document.write( "Larry is 1 and John is 3<BR>\n" );
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