document.write( "Question 921633: A car and a bus set out at 2pm from the same point headed in the same direction the average speed of the ca r is 30 mph slower than twice the speed of the bus. In two hours, the car is 20 miles ahead of the bus what is the speed of the car?\r
\n" ); document.write( "\n" ); document.write( "What i have done:
\n" ); document.write( "Suppose the speed of the bus is x. Then the speed of the car will be 2x-30.
\n" ); document.write( "We need to find speed so speed=Distance/Time.
\n" ); document.write( "Please help me after that as i am not able to proceed further.
\n" ); document.write( "The options are a)40mph b)50mph c)60mph d)70mph
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Algebra.Com's Answer #559127 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Your variable description for speeds of car and bus are inconvenient. Set r as the unknown speed of the bus. The speed then for the car is \"-30%2B2r\", or 2r-30 for the car. The car is going faster than the bus.\r
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\n" ); document.write( "\n" ); document.write( "__________________speeds__________time__________distance
\n" ); document.write( "CAR_______________2r-30___________2_____________\"%282r-30%29%2A2\"
\n" ); document.write( "BUS_________________r_____________2______________\"r%2A2\"\r
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\n" ); document.write( "\n" ); document.write( "The distance difference described makes for \"highlight%28%282r-30%292-r%2A2=20%29\".
\n" ); document.write( "Solve for r, which is the SPEED of the BUS.
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