document.write( "Question 921633: A car and a bus set out at 2pm from the same point headed in the same direction the average speed of the ca r is 30 mph slower than twice the speed of the bus. In two hours, the car is 20 miles ahead of the bus what is the speed of the car?\r
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document.write( "What i have done:
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document.write( "Suppose the speed of the bus is x. Then the speed of the car will be 2x-30.
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document.write( "We need to find speed so speed=Distance/Time.
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document.write( "Please help me after that as i am not able to proceed further.
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document.write( "The options are a)40mph b)50mph c)60mph d)70mph \n" );
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Algebra.Com's Answer #559127 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! Your variable description for speeds of car and bus are inconvenient. Set r as the unknown speed of the bus. The speed then for the car is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "__________________speeds__________time__________distance \n" ); document.write( "CAR_______________2r-30___________2_____________ \n" ); document.write( "BUS_________________r_____________2______________ \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The distance difference described makes for \n" ); document.write( "Solve for r, which is the SPEED of the BUS. \n" ); document.write( " |