document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=921588>Question 921588</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A plane left emerald city flying at an average rate of 270 mph. Two hours later, another plane left Emerald city in the same direction at 420 mph. How long will the second plane flying till catches up with the first? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #559083 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=559083\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Gaining speed 420-270= 150 mph<BR>\n" );
document.write( "Head start 270*2 =540 miles<BR>\n" );
document.write( "Time to catch up 540/150=3.6 hours<BR>\n" );
document.write( "Algebraic solution<BR>\n" );
document.write( "270(t+2)=420t<BR>\n" );
document.write( "270t+540=420t<BR>\n" );
document.write( "540=420t-270t<BR>\n" );
document.write( "540=150t<BR>\n" );
document.write( "t=3.6 hours<BR>\n" );
document.write( "Distance to meeting 3.6*420=1512 miles<BR>\n" );
document.write( "code drtch1<BR>\n" );
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