document.write( "Question 921525: a metal sphere with a volume of 900cm cubed is placed in a cylinder with a radius of 10cm containing a depth of 15cm of water. what is the height that the water level rises in cm? \n" ); document.write( "
Algebra.Com's Answer #559035 by lwsshak3(11628)\"\" \"About 
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a metal sphere with a volume of 900cm cubed is placed in a cylinder with a radius of 10cm containing a depth of 15cm of water. what is the height that the water level rises in cm?
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\n" ); document.write( "r=radius of cylinder
\n" ); document.write( "letv=original volume of water in cylinder
\n" ); document.write( "let h=height of water level in cylinder
\n" ); document.write( "volume of water in cylinder=cross-section area of cylinder*depth of water
\n" ); document.write( "v=πr^2*h=π*100*15=1500π cm^3
\n" ); document.write( "new volume=1500π+900
\n" ); document.write( "h=(1500π+900)/πr^2=(1500π+900)/100π=(15+9/π)=17.86
\n" ); document.write( "what is the height that the water level rises in cm? 17.86
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