document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=921476>Question 921476</A>: <I><SPAN STYLE=\"word-break: break-all;\"> X=2y-5 and Y=3x-5 then X+Y=?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #559007 by </B><A HREF=/tutors/aboutme.mpl?userid=mathsnight><B>mathsnight(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathsnight><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mathsnight><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=559007\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Substitute the given values simply:<BR>\n" );
document.write( "x=2(3x-5)-5<BR>\n" );
document.write( "=> x=3; for y,<BR>\n" );
document.write( "y=3x-5=3(3)-5=4.<BR>\n" );
document.write( "Then x+y=3+4=7. </SPAN>\n" );
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