document.write( "Question 77726: Please help\r
\n" ); document.write( "\n" ); document.write( "Suppose a baseball is shot up from the ground straight up with an initial velocity of 32 feet per second. A function can be created by expressing distance above the ground, s, as a function of time, t. This function is s = -16t2 + v0t + s0
\n" ); document.write( "• 16 represents ½g, the gravitational pull due to gravity (measured in feet per second 2).
\n" ); document.write( "• v0 is the initial velocity (how hard do you throw the object, measured in feet per second).
\n" ); document.write( "• s0 is the initial distance above ground (in feet). If you are standing on the ground, then s0 = 0.
\n" ); document.write( "a) What is the function that describes this problem?\r
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\n" ); document.write( "\n" ); document.write( "b) The ball will be how high above the ground after 1 second?
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\n" ); document.write( "\n" ); document.write( "c) How long will it take to hit the ground?\r
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\n" ); document.write( "\n" ); document.write( "d) What is the maximum height of the ball?
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Algebra.Com's Answer #55899 by renevencer22(21)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "a) this function describes displacement as, s = Vo*t - (1/2)*g*t^2, showing effect of gravity in motion of (falling and going-up ) body. It is in terms of initial velocity and gravity at any time.
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\n" ); document.write( "see also: http://www.freewebs.com/renevencer11/-%20math/freefalling.jpg
\n" ); document.write( "note: copy, paste on your file & Ctrl+ click to view the link
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\n" ); document.write( "b) after 1 sec s = Vo*t - (1/2)*g*t^2
\n" ); document.write( "Vo = 32 ft/sec s = 32*1 - (1/2)*32.2*1^2 = 15.90 ft
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\n" ); document.write( "d) maximum height
\n" ); document.write( "V1^2 - Vo^2 = -2*g*h V1 = final velocity, equal to zero at maximum height
\n" ); document.write( "h = Vo^2/(2*g) = 15.90 ft
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\n" ); document.write( "c) it becomes a free-falling body
\n" ); document.write( "s = Vo*t + (1/2)*g*t^2 V0 = 0
\n" ); document.write( "15.90 = (1/2)*32.2*t^2 =
\n" ); document.write( "t = sqrt(15.9 /(16.1))= 0.9938 sec
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