document.write( "Question 921397: Hi there, I've been trying and trying this problem with no luck. Could you help me out with this, please?\r
\n" ); document.write( "\n" ); document.write( "Given the function y=(x-11)^2, where x is less than or equal to 11, find the inverse and its domain. \r
\n" ); document.write( "\n" ); document.write( "I keep getting y=plus or minus sqrt(x)-1 which is incorrect.
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Algebra.Com's Answer #558955 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
The domain of the original function is \"x%3C=11\". This is given to you and this restriction is made to force f(x) to be one-to-one.\r
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\n" ); document.write( "\n" ); document.write( "The range of the original function is \"y%3E=0\". This is found either through the graph or by knowing that (x-11)^2 is either 0 or positive. You can't square a number and get something negative.\r
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\n" ); document.write( "\n" ); document.write( "When you solve for the inverse, you swap x and y and solve for y. Doing that also swaps the domain and range. Why? Because the domain is simply the set of allowed x values (inputs) and the range is the set of possible y values (outputs).\r
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\n" ); document.write( "\n" ); document.write( "Again, the domain and range swap. This is important.\r
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\n" ); document.write( "\n" ); document.write( "So the inverse will have the domain of \"x+%3E=+0\" and the range of \"y+%3C=+11\"\r
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\n" ); document.write( "\n" ); document.write( "The range for the inverse is what is important here. \r
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\n" ); document.write( "\n" ); document.write( "When you swap x and y, then solve for y, you should get this: \"y+=+%22%22%2B-sqrt%28x%29%2B11\"\r
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\n" ); document.write( "\n" ); document.write( "But keep in mind that the range of the inverse is \"y+%3C=+11\". This means negative y values such as \"y+=+-2\" are possible in the range of the inverse.\r
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\n" ); document.write( "\n" ); document.write( "This is only possible if you pick the negative square root. You cannot generate negative y values with \"y+=+sqrt%28x%29%2B11\". It's impossible. The two pieces are always positive.\r
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\n" ); document.write( "\n" ); document.write( "So the inverse is \r
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\n" ); document.write( "\n" ); document.write( "You can rewrite that as \r
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\n" ); document.write( "\n" ); document.write( "Let me know if that helps or not. Thanks.\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, feel free to email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "My Website: http://www.freewebs.com/jimthompson5910/home.html\r
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