document.write( "Question 921311: In a rational number, twice the numerator is 2 more than the denominator. If 3 is added to each, the numerator and the denominator, the new fraction is 2/3. Find the original number. \n" ); document.write( "
Algebra.Com's Answer #558920 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "start with \"a%2Fb\"\r
\n" ); document.write( "\n" ); document.write( "twice the numerator (\"2a\") is \"2\" more than the denominator ( \"b\"): \r
\n" ); document.write( "\n" ); document.write( "\"2a=b%2B2\" =>\"a=b%2F2%2B1\"\r
\n" ); document.write( "\n" ); document.write( " the new fraction is \"a%2Fb=%28b%2F2%2B1%29%2Fb\"\r
\n" ); document.write( "\n" ); document.write( "\"3\" is added to each\r
\n" ); document.write( "\n" ); document.write( "\"%28%28b%2F2%2B1%29%2B3%29%2F%28b%2B3%29\" and it is equal to \"2%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"%28%28b%2F2%2B1%29%2B3%29%2F%28b%2B3%29+=2%2F3\" .........solve for \"b\"\r
\n" ); document.write( "\n" ); document.write( "\"%28b%2F2%2B4%29%2F%28b%2B3%29+=2%2F3+\"\r
\n" ); document.write( "\n" ); document.write( "\"3%28b%2F2%2B4%29+=2%28b%2B3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"3b%2F2%2B12+=2b%2B6\"\r
\n" ); document.write( "\n" ); document.write( "\"12-6+=2b-3b%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"6=4b%2F2-3b%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"6+=b%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"6%2A2+=b\"\r
\n" ); document.write( "\n" ); document.write( "\"12=b\"\r
\n" ); document.write( "\n" ); document.write( "=>\"a=b%2F2%2B1\" => \"a=12%2F2%2B1\" => \"a=6%2B1\"=>\"a=7\"\r
\n" ); document.write( "\n" ); document.write( "original fraction is: \"a%2Fb=7%2F12\"\r
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