document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=920830>Question 920830</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if sin x = -12/13 with  pie < x < 3pi/2 then sin (pie/3 + x)  = ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #558903 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=558903\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if sin t = -12/13 with pie < t < 3pi/2 then sin (pie/3 + t) = ?<BR>\n" );
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document.write( "x and y are negative in QIII<BR>\n" );
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document.write( "By definition, sin = y/r<BR>\n" );
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document.write( "Since sin = -12/13, y = -12 and r = 13<BR>\n" );
document.write( "Then x = -sqrt[13^2 - 12^2] = -5<BR>\n" );
document.write( "So cos(t) = -5/13<BR>\n" );
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document.write( "Your Problem::<BR>\n" );
document.write( "sin(pi/3 + t) = sin(pi/3)cos(t) + cos(pi/3)sin(t)<BR>\n" );
document.write( "= sqrt(3)/2*(-5/13) + (1/2)*-12/13<BR>\n" );
document.write( "etc.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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