document.write( "Question 921246: Please help!
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document.write( "The graph of one complete period of a sine and cosine curve is given.?
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document.write( "please explain how to fill out these graphs thank you \r
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document.write( "http://i.imgur.com/rCXQUym.png
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document.write( "http://i.imgur.com/X1cZq8F.png \n" );
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Algebra.Com's Answer #558884 by Theo(13342)![]() ![]() You can put this solution on YOUR website! your first picture is shown below:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the interval goes from 0 to 4p/4 which is the same as from 0 to pi.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the period is therefore equal to pi.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the frequency is equal to 2pi / pi = 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "there is no phase shift because cosine = 1 at 0 radians which is the value shown on the graph.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the equation in the form of y = a * cos (k(x-b)) becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 6 * cos(2 * x)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i graphed it to confirm.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that graph is shown below:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can see the equation on the top left.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the graph matches your picture so it looks good.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your second picture is shown below:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the amplitude is 6.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the interval goes from -3/4 to 1/4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the period is therefore equal to 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the frequency is equal to 2pi / 1 = 2pi.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the sine wave should be 0 when x = 0.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this sine wave appears to be shifted to the right by 1/4 of the period.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the phase shift is therefore equal to 1/4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the equation in the form of y = a * sin (k * (x-b)) becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 6 * sin(2pi * (x-1/4))\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the graph of that equation is shown below:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |