document.write( "Question 77990: I can't figure out this hyperbola: (((3x^2 + y^2 +18x - 2y + 4=0))). This is what I've tried so far: 3x^2/3 + y^2 + 18x/3 - 2y +4=0
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document.write( " x^2 +y^2 + 6x - 2y =-4
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document.write( " x^2/-4 + y^2/-4 + -3x/2 + y/2 = 1)))
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document.write( "please help me \n" );
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Algebra.Com's Answer #55888 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 3x^2 + y^2 +18x - 2y + 4=0 \n" ); document.write( "Complete the square for the x-terms and for the y-terms separately. \n" ); document.write( "--------- \n" ); document.write( "3(x^2+6x+9) + y^2-2y+1) = -4+27+1 \n" ); document.write( "3(x+3)^2 + (y-1)^2 = 24 \n" ); document.write( "Divide thru by 24 to get the form of a hyperbola. \n" ); document.write( "[(x+3)^2]/8 + [(y-1)^2]/24 = 1 \n" ); document.write( "========= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |