document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=921200>Question 921200</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In still water, a boat averages 5 miles per hour. It takes the same amount of time to travel 14 miles downstream, with the current, as 6 miles upstream, against the current. What is the rate of the water's current? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #558842 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=558842\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=14%2F%285%2Bc%29+=+6%2F%285-c%29 ALIGN=MIDDLE  ALT=\"14%2F%285%2Bc%29+=+6%2F%285-c%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >| Cross Multiplying to solve<BR>\n" );
document.write( "14(5-c) = 6(5+c)<BR>\n" );
document.write( "70-14c = 30 + 6c<BR>\n" );
document.write( "40 = 20c<BR>\n" );
document.write( "2mph  = c <BR>\n" );
document.write( "and...checking<BR>\n" );
document.write( "14mi/7mph = 6mi/3mph = 2hr   </SPAN>\n" );
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