document.write( "Question 920724: y=-(x+3)^2-4\r
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Algebra.Com's Answer #558760 by srinivas.g(540)\"\" \"About 
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y= -(x+3)^2 -4
\n" ); document.write( " y =-(x+3)*(x+3) -4
\n" ); document.write( " y = -(x(x+3)+3(x-3) -4
\n" ); document.write( " y = -(x^2+3x+3x+3*3)-4
\n" ); document.write( " y= -(x^2+6x+9)-4
\n" ); document.write( " y= -X^2-6x-9-4
\n" ); document.write( " y =-x^2-6x-13
\n" ); document.write( " solve the quadratic equation
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"-1x%5E2%2B-6x%2B-13+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-6%29%5E2-4%2A-1%2A-13=-16\".
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\n" ); document.write( " The discriminant -16 is less than zero. That means that there are no solutions among real numbers.

\n" ); document.write( " If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

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\n" ); document.write( " In the field of imaginary numbers, the square root of -16 is + or - \"sqrt%28+16%29+=+4\".
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\n" ); document.write( " The solution is \"x%5B12%5D+=+%28--6%2B-+i%2Asqrt%28+-16+%29%29%2F2%5C-1+=++%28--6%2B-+i%2A4%29%2F2%5C-1+\"
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\n" ); document.write( " Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+-1%2Ax%5E2%2B-6%2Ax%2B-13+%29\"

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