document.write( "Question 921157: 4x^2+24x-13 converted into vertex form
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Algebra.Com's Answer #558759 by srinivas.g(540)\"\" \"About 
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The vertex form of a parabola is given by y = a(x - h)^2 + k, a ≠ 0.
\n" ); document.write( "standard form is y= ax^2+bx+c
\n" ); document.write( "Comparing with the standard form of parabola, f(x) = ax^2 + bx + c, we get
\n" ); document.write( "a = 4.
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\n" ); document.write( " given equation y= 4x^2+24x-13
\n" ); document.write( " y = (2x)^2 -2*2x*6-13
\n" ); document.write( " to make it perfect square add 6^2 and subtract 6^2
\n" ); document.write( " y = (2x)^2 -2*2x*6-13+6^2-6^2\r
\n" ); document.write( "\n" ); document.write( " y=(2x)^2 -2*2x*6+6^2 -13-6^2
\n" ); document.write( " y= (2x-6)^2-13-36
\n" ); document.write( " y =(2x-6)^2 -49
\n" ); document.write( " take 2 out side in square term
\n" ); document.write( " y = 2^2 *( x-3)^2 -49\r
\n" ); document.write( "\n" ); document.write( " y= 4 (x-3)^2-49
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