document.write( "Question 77870: The height of an object dropped from a 205 feet tall building is given by h = -16t squared + 205. When will the object be 36 feet above the ground \n" ); document.write( "
Algebra.Com's Answer #55874 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The height of an object dropped from a 205 feet tall building is given by h = -16t squared + 205. When will the object be 36 feet above the ground \n" ); document.write( "0 solutions \n" ); document.write( ": \n" ); document.write( "Substitute 36 for h: \n" ); document.write( "-16t^2 + 205 = 36 \n" ); document.write( ": \n" ); document.write( "-16t^2 = 36 - 205; Subtract 205 from both sides \n" ); document.write( ": \n" ); document.write( "16t^2 = 169; multiplied equation by -1 \n" ); document.write( ": \n" ); document.write( "sqrt(16t^2) = sqrt(169); find the square root of both sides \n" ); document.write( ": \n" ); document.write( "4t = 13 \n" ); document.write( ": \n" ); document.write( "t = 13/4 \n" ); document.write( ": \n" ); document.write( "t = 3.25 seconds it will be 36 ft above the ground: \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check by substituting 3.25 for x, in -16t^2 + 205 \n" ); document.write( "-16(3.25^2) + 205 = \n" ); document.write( "-16(10.5625) + 205 \n" ); document.write( "-169 + 205 = 36 \n" ); document.write( " |