document.write( "Question 921118: a train leaves a station and travels east at 40km/h three hours later a second train leaves on a parallel track traveling east at 60km/h how far away from the station do the trains meet? \n" ); document.write( "
Algebra.Com's Answer #558720 by mananth(16946)![]() ![]() You can put this solution on YOUR website! the distance traveled by both is same when one catches up with the other. \n" ); document.write( "Let them meet at distance x \n" ); document.write( "Train A speed= 40 km/h \n" ); document.write( "Train B speed= 60 km/h \n" ); document.write( " \n" ); document.write( "Time difference between the starting of the two= 3.00 hours \n" ); document.write( " \n" ); document.write( "Time taken by Train A = X / 40 \n" ); document.write( "Time taken by Train B = X / 60 \n" ); document.write( " \n" ); document.write( "X / 40 - X / 60 = 3 \n" ); document.write( " \n" ); document.write( "LCD - 90 \n" ); document.write( "Multiply equation by 90 90 \n" ); document.write( " \n" ); document.write( "2.25 x - 1.5 x = 270 \n" ); document.write( "0.75 x = 270 \n" ); document.write( "/ 0.75 \n" ); document.write( "x= 360 km \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Train B speed= 60 km/h \n" ); document.write( "Distance = 360 miles \n" ); document.write( "Time taken = 360 / 60 \n" ); document.write( "Time taken = 6 hours \n" ); document.write( " \n" ); document.write( " |