document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=921118>Question 921118</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a train leaves a station and travels east at 40km/h three hours later a second train leaves on a parallel track traveling east at 60km/h how far away from the station do the trains meet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #558718 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=558718\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a train leaves a station and travels east at 40km/h three hours later a second train leaves on a parallel track traveling east at 60km/h how far away from the station do the trains meet?<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "1st train DATA:<BR>\n" );
document.write( "rate = 40 km/hr ; time = x hrs ; distance = 40x km<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "2nd train DATA:<BR>\n" );
document.write( "rate = 60 km/hr ; time = x-3 hrs ; distance = 60(x-3) km<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "40x = 60x - 180<BR>\n" );
document.write( "-20x = -180<BR>\n" );
document.write( "x = 9 hrs (time for later train to catch up to earlier train)<BR>\n" );
document.write( "------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );