document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=921120>Question 921120</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a cow eats 7 bags of feed in 9 days.how long will 12 cow take to eat the 7 bags<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #558716 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=558716\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3/4a cow eats 7 bags of feed in 9 days.how long will 12 cow take to eat the 7 bags<BR>\n" );
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document.write( "t is inversely propotional to # of cows and directly proportional to # of bags.<BR>\n" );
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document.write( "t = k*b/c<BR>\n" );
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document.write( "Solve for \"k\" using \"a cow eats 7 bags in 9 days\"::<BR>\n" );
document.write( "9 = k*7/1<BR>\n" );
document.write( "k = 9/7<BR>\n" );
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document.write( "Equation::<BR>\n" );
document.write( "t = (9/7)b/c<BR>\n" );
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document.write( "How long will 12 cow take to eat the 7 bags<BR>\n" );
document.write( "t = (9/7)7/12<BR>\n" );
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document.write( "t = 9/12 = 3/4 of a day<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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