document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=921046>Question 921046</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Just not getting this.\r<BR>\n" );
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document.write( "Suppose cos t = -0.4 and csc t < 0 . Find each of the following \r<BR>\n" );
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document.write( "sin t = <BR>\n" );
document.write( "tan t = <BR>\n" );
document.write( "csc t = <BR>\n" );
document.write( "sec t = <BR>\n" );
document.write( "cot t = \r<BR>\n" );
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document.write( "I know cos = -4/10 = -2/5 <BR>\n" );
document.write( "and csc = 1/y and this states that csc<0 so I'd think that is saying y must be negative. \r<BR>\n" );
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document.write( "cos = adj/hyp so I use Pythagorean theorem and since y is negative I know it must be in either III or IV quadrant but which is negative out of cos the 2 or 5? I think it's the 5. Which I go to figure out the opposite I run into this problem: \r<BR>\n" );
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document.write( "b = &#8730;(-5^2 + 2^2) <BR>\n" );
document.write( "b = &#8730;(-25+4) <BR>\n" );
document.write( "b = &#8730;(-21) \r<BR>\n" );
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document.write( "But I can't square a negative? <BR>\n" );
document.write( "What am I misunderstanding here? \r<BR>\n" );
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document.write( "I know the answer for b is -&#8730;21/5 I just don't know how to get that </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #558692 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=558692\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose cos t = -0.4 and csc t < 0 . Find each of the following<BR>\n" );
document.write( "sin t =<BR>\n" );
document.write( "tan t =<BR>\n" );
document.write( "csc t =<BR>\n" );
document.write( "sec t =<BR>\n" );
document.write( "cot t = <BR>\n" );
document.write( "***<BR>\n" );
document.write( "Given data shows reference angle t is in quadrant III in which cos<0, sin<0<BR>\n" );
document.write( "cos t=-0.4=-4/10=-2/5<BR>\n" );
document.write( "sin t=-&#8730;(1-cos^2t)=-&#8730;(1-4/25)=-&#8730;(21/25)=-&#8730;21/5<BR>\n" );
document.write( "tan t=sin/cos=-&#8730;21/-2=&#8730;21/2<BR>\n" );
document.write( "sec t=-5/2<BR>\n" );
document.write( "csc t=-5/&#8730;21=-5&#8730;21/21<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );