document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=920975>Question 920975</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tisha has 11 coins worth $6.25. If the coins are all loonies and nickels, how many loonies and nickels does she have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #558668 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=558668\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Not knowing the value of a loony, this could give an inequality  (because of the limited nickels value) and then two equations in three unknowns.  Playing with the given values all in the head, if a loony is 1.00 dollar, then 6 loonies is $6.00, and that leaves remaining 0.25 dollars, which could be worth 5 nickels.  There are your 11 coins:  \r<BR>\n" );
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document.write( "6 loonies plus 5 nickes, making 11 coins, and value sum to $6.25.\r<BR>\n" );
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document.write( "I could not find a more formal arithmetic method. </SPAN>\n" );
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