document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=920800>Question 920800</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bobby is 3 years older than Chris. Last year, the sum of their ages was 39. how old is each now?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #558598 by </B><A HREF=/tutors/aboutme.mpl?userid=multiplier><B>multiplier(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=multiplier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=558598\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x- age of chris at present<BR>\n" );
document.write( "    (x+3)- age of bobby at present, we add 3 to chris's age bec. he is 3 years younger than bobby<BR>\n" );
document.write( "    last year the sum of their ages is 39\r<BR>\n" );
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document.write( "    before we get the sum of their ages which is equal to 39, we must subtract 1 year from their ages <BR>\n" );
document.write( "    (x-1) - age of chris last year<BR>\n" );
document.write( "    {(x+3)-1} - age of boby last year<BR>\n" );
document.write( "proceeding to addition,<BR>\n" );
document.write( "    (x-1) + ({x+3}-1)=39<BR>\n" );
document.write( "  x=19 age of chris at present<BR>\n" );
document.write( "  x+3=19+3=22 age of bobby at present  </SPAN>\n" );
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