document.write( "Question 920810:  I have two problems with factorization. I tried everything, in many ways, but can't find the right answer.\r
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document.write( "First:
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document.write( "The answer is:
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document.write( "Second:
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document.write( "Answer:
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document.write( "Thank you! \n" );
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| Algebra.Com's Answer #558586 by rothauserc(4718)     You can put this solution on YOUR website! 1) We can factor the sum of cubes using the following formula: \n" ); document.write( "x^3 + y^3 = (x+y)(x^2-xy+y^2) \n" ); document.write( "we are given (x-1)^3 + 2^3 \n" ); document.write( "therefore we get \n" ); document.write( "(x-1+2)((x-1)^2 -(x-1)2 +4)) \n" ); document.write( "(x+1)(x^2-2x+1 -2x +2 +4) \n" ); document.write( "(x+1)(x^2 -4x +7) \n" ); document.write( "2) Let a = x^2 \n" ); document.write( "Let b = y^2. \n" ); document.write( "So lets substitute the values of a and b in for x^2 and y^2: \n" ); document.write( "a^2 + ab + y^2 \n" ); document.write( "If you know that (a + b)^2 = a^2 + 2ab + b^2, then you can see that the two expressions are similar. \n" ); document.write( "lets just add one set of \"ab\" to the first equation, so that we get a^2 + 2ab + b^2, which is easily simplified. \n" ); document.write( "therefore, we would get: \n" ); document.write( "(a + b)^2 - ab <----if we added ab, we must now subtract it. \n" ); document.write( "now, just substitute the values of a and b back in: \n" ); document.write( "(x^2 + y^2)^2 - x^2y^2 then apply the difference of squares here. \n" ); document.write( "(x^2 + y^2) - (xy)^2 \n" ); document.write( "(x ^2 + y^2 + xy) (x^2 + y^2 - xy) \n" ); document.write( " |