document.write( "Question 920768: A car travels from P to Q at a constant speed. If its speed were increased by 10 km/h, it would have been taken one hour lesser to cover the distance. It would have taken further 45 minutes lesser if the speed was further increased by 10 km/h. the distance between the two cities is\r
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Algebra.Com's Answer #558580 by multiplier(8)\"\" \"About 
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let v- constant speed of car in km/hr
\n" ); document.write( " s- distance between the two cities(P to Q) in kilometers
\n" ); document.write( " t- time to travel from P to Q in hours
\n" ); document.write( " working formula: s=vt
\n" ); document.write( " cond. 1: s=vt >(Eq 1)
\n" ); document.write( " cond. 2: v is increase by 10 km/hr, the value of (v) in (Eq 1) becomes
\n" ); document.write( " (v+10), and (t) in will be (t-1)
\n" ); document.write( " s=(v+10)(t-1) > (Eq 2)
\n" ); document.write( " cond. 3:v is increased further by 10km/hr, time is cut by 45 minutes
\n" ); document.write( " s=(v+20)(t-7/4) >(Eq 3)... (7/4= 1 hr and 45 minutes)
\n" ); document.write( " since distance from P & Q is constant, s will be same in all conditions
\n" ); document.write( " equate (Eq 1), (Eq 2) and (Eq 3)
\n" ); document.write( " v=60km/hr; t=7 hours
\n" ); document.write( " s=420 km-the distance you are looking for...
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