document.write( "Question 920777: 62% of students in a class are male, seven of the student in the student the class are chosen at random. What is the probability that
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document.write( "a) they are all females?
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document.write( "b) they are all males?
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document.write( "c) at least on is a female? \n" );
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Algebra.Com's Answer #558566 by Theo(13342)![]() ![]() You can put this solution on YOUR website! if 62% are male then 38% are female since 62 + 38 = 100%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "probability of all females is equal to .38^7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "probability all males is equal to .62^7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "probability at least 1 female = 1 - probability all male = 1 - .62^7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "^ is the symbol used for exponentiation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".38^7 means .38 raised to the 7th power.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".38^7 = .0011 rounded to 4 decimal places. \n" ); document.write( ".62^7 = .0352 rounded to 4 decimal places.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1 - .62^7 = 1 - .0352 = .9648 rounded to 4 decimal places.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".38^7 means .38 * .38 * .38 * .38 * .38 * .38 * .38\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "7 instances of .38 are multiplied by each other.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the number of multiplications performed is 7 - 1 = 6.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |