document.write( "Question 920749: 12x^2-29x+15=0 ( Factor) \n" ); document.write( "
Algebra.Com's Answer #558560 by MathTherapy(10552)\"\" \"About 
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12x^2-29x+15=0 ( Factor)
Using the \"ac\" method to factor the left-side trinomial, we need to find 2 factors with a 
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document.write( "PRODUCT of + 180 (+ 12 * + 15), and a sum of - 29 (b). These 2 factors are: - 20 and - 9
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document.write( "12x2 - 29x + 15 = 0 becomes:
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document.write( "12x2 - 20x - 9x + 15 = 0 ------- Replacing - 29x with - 20x - 9x
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document.write( "4x(3x - 5) - 3(3x - 5) = 0 ------ Factoring out the GCF of the 1st 2 terms, and the 2nd 2 terms
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document.write( "(4x - 3)(3x - 5) = 0 ------------- Factored form of the trinomial
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document.write( "4x - 3 = 0                OR             3x - 5 = 0
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document.write( "From here, you can determine the 2 values of x, if that's your goal.   \n" );
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