document.write( "Question 77946: A merchant wishes to mix candy worth $5 per lb with 40lb of candy worth $2 per pound to get a mixture that can be sold for $3 per lb. How many pounds of $5 candy should be used? \n" ); document.write( "
Algebra.Com's Answer #55854 by checkley75(3666)\"\" \"About 
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5X+2*40=3(40+X)
\n" ); document.write( "5X+80=120+3X
\n" ); document.write( "5X-3X=120-80
\n" ); document.write( "2X=40
\n" ); document.write( "X=40/2
\n" ); document.write( "X=20 POUNDS OF $5 CANDY IS NEEDED.
\n" ); document.write( "PROOF
\n" ); document.write( "5*20+2*40=3*60
\n" ); document.write( "100+80=180
\n" ); document.write( "180=180
\n" ); document.write( "
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