document.write( "Question 77946: A merchant wishes to mix candy worth $5 per lb with 40lb of candy worth $2 per pound to get a mixture that can be sold for $3 per lb. How many pounds of $5 candy should be used? \n" ); document.write( "
Algebra.Com's Answer #55854 by checkley75(3666) ![]() You can put this solution on YOUR website! 5X+2*40=3(40+X) \n" ); document.write( "5X+80=120+3X \n" ); document.write( "5X-3X=120-80 \n" ); document.write( "2X=40 \n" ); document.write( "X=40/2 \n" ); document.write( "X=20 POUNDS OF $5 CANDY IS NEEDED. \n" ); document.write( "PROOF \n" ); document.write( "5*20+2*40=3*60 \n" ); document.write( "100+80=180 \n" ); document.write( "180=180 \n" ); document.write( " |