document.write( "Question 920664: Find two consecutive odd integers such that seven times the first is eight more than 5 times the second.\r
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document.write( "my answer ; 7x = [5(x+2)] + 8 \n" );
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Algebra.Com's Answer #558523 by josgarithmetic(39625) ![]() You can put this solution on YOUR website! Odd consecutive integers, 2n+1, 2n+3 for any Natural Number n.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The trouble with your equation compared to this one is that you used variable expressions that \n" ); document.write( "would not ensure to be odd numbers. You can now continue with the equation and solve for n \n" ); document.write( "and then evaluate 2n+1 and 2n+3. \n" ); document.write( " \n" ); document.write( " |